“Kerbs
Cycle”
1)
Pyruvate in cytosol will go through reactions and will convert to 2 carbon
molecules. One of the 3 carbons in pyruvate will be released as carbon dioxide.
The remainder is called Acetyl group that will combine to coenzyme A (co-A) and
will provide Acetyl-CoA
2)
It is a cyclical metabolic pathway occurs in mitochondria matrix
3)
During this cycle the carbon atom from
glucose that entered to the glycolysis will be oxidized.
4)
This cycle has made of 9 step reactions with following names :
Reaction 1:
condensation
Reaction 2 and 3:
Isomerization
Reaction 4: The first Oxidation
Reaction 5: The second
Oxidation
Reaction 6: Substrate-
level phosphorylation
Reaction 7: The third
Oxidation
Reaction 8 and 9: Regeneration of oxaloacetate and the fourth
Oxidation
5) For each glucose, 2 acetyl-CoA
will enter the kerbs cycle that carries 2 carbons
6) Acetyl will react to
oxaloacetate to produce citrate (6 carbon molecule)
7) This molecule
(citrate) will go through 5 series of reactions and 4 carbon molecules called
succinate will be forms. 2 of the reactions are oxidation reaction and will
release 2 carbon dioxides. 2 of the reactions are reduction reactions which
produce NADH from reduction of NAD.
8) In the 6th
stage, ATP will be produced by (substrate-level phosphorylation). In this
process phosphate group replace CoA and substrate succinct will bound to the
enzyme. Phosphate will be added to (GTP) and terminal of (GTP) will be transferred
to ADP to produce ATP. In somce cells, cell will use GTP to make their own
energy.
9) 2 of the actions
that will take place from stage 7-9 are oxidation. These electrons will be used
to produce ATP in the oxidative phosphorylation pathway. This reaction is coupled
to reduction of NAD to form NADH and FAD to form FADH2.
10) The last product of
all of the reactions is oxaloacetate. It will be ready to react to more Acetyl-CoA
that will be entered the kerbs cycle.